Question

how much iron can be recovered from 25 grams of Fe2O3

Answer 1

Answer: The mass of iron recovered is 17.5 grams

Explanation:

We are given a chemical compound having chemical formula of $Fe_2O_3$

We know that:

Molar mass of iron (III) oxide = 159.7 g/mol

Mass of iron = 55.8 g/mol

We are given:

Mass of iron (III) oxide = 25 g

To calculate the mass of iron recovered in given amount of iron (III) oxide, we use unitary method:

From 159.7 grams of iron (III) oxide, mass of iron recovered is $(2\times 55.8)g$

So, from 25 grams of iron (III) oxide, mass of iron recovered will be $\frac{(2\times 55.8)}{159.7}\times 25=17.5g$

Hence, the mass of iron recovered is 17.5 grams

Answer 2

The iron that will be recovered from 25 g of $\bold{Fe_2O_3}$ is

What is ferric oxide?

Ferric oxide is an organic compound with the chemical formula $\bold{Fe_2O_3}$. It is one of the three main oxides of iron.

Given,

Mass of $\bold{Fe_2O_3}$ is 25 gram

Molar mass of iron oxide is 159.7

Mass of iron is 55.8 g

To calculate the amount of iron

From 159.7 g of ferric oxide, the amount of iron we found is $55.8\;g \times 2$

So, from 25 grams of ferric oxide, the mass of iron recovered will be

$\dfrac{55.8 \times 2}{159.7} \times25 = 17.5 g$

Thus, the mass of iron recovered is 17.5 g.

Learn more about ferric oxide, here:

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