Question

What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr] 5s2 5d10 5p6 6s2 6d10 6p3 E. [Xe] 6s2 5d10 6p3

Answer 1

The answer is C) Xe 4f14 5d10 6s2 6p3

Answer 2

Answer: C. $[Xe] 4f^{14}5d^{10}6s^26p^3$

Explanation: Bismuth is an element with atomic number of 83 and contains  83 electrons. The nearest noble gas is Xenon with symbol $Xe$ and contains 54 electrons.

The electronic configuration of Bismuth in terms of nearest noble gas $Bi$ is :

$[Xe] 4f^{14}5d^{10}6s^26p^3$