You can solve this by utilizing the ideal gas law, PV=nRT. P is pressure, V is volume, n is the number of moles, R is a constant (depends on the unit of pressure), and T is the temperature (in Kelvins).
500.0mmHg- convert to atm
=0.65789atm (do sig figs last)
25.0 C- convert to K
25.0 +273= 298K
PV=nRT
0.65789atm times 45.0L equals n (the variable) times R (0.08206L atm mol^-1 K^-1) times 298K
Isolate the variable, n and plug into a calculator.
I hope this helped!
Answer: The moles of gas is 1.21 moles.
Explanation:
To calculate the moles of gas, we use the equation given by ideal gas which follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 500.0 mmHg
V = Volume of the gas = 45.0 L
T = Temperature of the gas = [tex]25^oC=[25+273]K=298K[/tex]
R = Gas constant = [tex]62.364\text{ L.mmHg }mol^{-1}K^{-1}[/tex]
n = number of moles of gas = ?
Putting values in above equation, we get:
[tex]500.0mmHg\times 45.0L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{500.0\times 45.0}{62.364\times 298}=1.21mol[/tex]
Hence, the moles of gas is 1.21 moles.
