Question

What force is needed to keeps 20kg box moving at a constant velocity when the mk is 0.3021 and the force is applied level to the ground

Answer 1

Answer:

59.2 N

Explanation:

According to Newton's second law, the resultant of the forces acting on the box must be equal to the product between the box's mass and its acceleration:

$F_{net}=ma$

However, the box is moving at constant velocity, so its acceleration is zero:

a = 0

Therefore, the net force along the direction of motion (parallel to the surface) must be zero.

We have two forces acting along the direction parallel to the ground:

- The applied force, F

- The frictional force, $\mu mg$, in the opposite direction, with $\mu = 0.3021$ being the coefficient of friction, m = 20 kg the mass of the box and g = 9.8 m/s^2

Therefore, the equation of motion becomes:

$F-\mu mg=0$

And solving for F, we find:

$F=\mu mg=(0.3021)(20 kg)(9.8 m/s^2)=59.2 N$