now, recalling the pythagorean theorem a little.
the hypotenuse here is 8√2, and then we have the other two sides, BUT, the opposite angle for each is actually the same 45°, if each opposite angle is the same, the length of the side on the other end is also the same.
so we have say side "b" and side "a", but because each has an opposite angle of 45°, that means "b" and "a" are actually twins.
[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies (8\sqrt{2})^2=a^2+b^2 \qquad \begin{cases} c=\stackrel{hypotenuse}{8\sqrt{2}}\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \stackrel{\textit{since we know that \underline{a = b}}}{[8^2(\sqrt{2})^2]=a^2+a^2}\implies 64(2)=2a^2\implies \cfrac{64(2)}{2}=a^2\implies 64=a^2 \\\\\\ \sqrt{64}=a\implies 8=a=b[/tex]
