Answer: The probability of selecting a chip with an even number given that the chip is black = 5/6
Step-by-step explanation:
Let B represents the event of getting black chip,
While E represents the event of getting even chip.
So, according to the question,
It is given, The probability of selecting a black chip with an even number is,
[tex]P(B\cap E)=\frac{1}{2}[/tex]
And, The probability of selecting a black chip is,
[tex]P(B)=\frac{3}{5}[/tex]
Thus, the probability of selecting a chip with an even number given that the chip is black,
[tex]P(\frac{E}{B} )= \frac{P(B\cap E)}{P(B)} = \frac{1/2}{3/5}[/tex] ( By the conditional property )
⇒ [tex]P(\frac{E}{B} )= \frac{5}{6}[/tex]