Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Find the area of a regular hexagon with the given measurement. 48-inch perimeter A = sq. in.

Answer 1

Answer:

 

Step-by-step explanation:

It is given that the perimeter of the regular hexagon is 48 inch. Thus,

Perimeter of the regular hexagon = 48

⇒$Sum of all the sides=48$

⇒$6x=48$

⇒$x=8inch$

Thus, the side of the regular hexagon is 8 inch.

Now, $area of the regular hexagon=\frac{3\sqrt{3}}{2}(x)^2$

⇒$A=\frac{3\sqrt{3}}{2}(8)^2$

⇒$A=\frac{3\sqrt{3}}{2}(64)$

⇒$A=96\sqrt{3}$

⇒$A=166.03 sq inches$

Thus, the area of the regular hexagon is 166.03 sq inches.

Answer 2

The area of the regular hexagon that's given will be 166.03 inches².

How to calculate the area of the hexagon

From the information, it was stated that the regular hexagon has a perimeter of 48 inches.

Therefore, the length of each side will be:

= 48/6

= 8 inches

The area of a regular hexagon calculated as:

= 3✓3/2 × x²

= 3✓3/2 × 8²

= 96✓3

= 166.03

In conclusion, the area is 166.03 inches².

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