Answer:
x = - 6 or x = 1
Step-by-step explanation:
given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0
then the equation can be solved using the quadratic formula
• x = ( - b ± [tex]\sqrt{b^2-4ac}[/tex]) / 2a
x² + 5x - 6 = 0 is in standard form
with a = 1, b = 5 and c = - 6
x = (- 5 ± [tex]\sqrt{5^2-(4(1)(-6)}[/tex]) / 2
= (- 5 ± [tex]\sqrt{25+24}[/tex]) / 2
= (- 5 ± [tex]\sqrt{49}[/tex]) / 2
x = [tex]\frac{-5-7}{2}[/tex] = [tex]\frac{-12}{2}[/tex] = - 6
or x = [tex]\frac{-5+7}{2}[/tex] = [tex]\frac{2}{2}[/tex] = 1
