bunnyb93
bunnyb93 bunnyb93
  • 17-12-2018
  • Mathematics
contestada

How would I put equations like these in Standard Form?

4x-y-7=0
3x+9= (7/2)y
y=-4x+12
y=(-3/4)x+(5/4)

Respuesta :

gmany
gmany gmany
  • 31-12-2018

The standard form:

[tex]Ax+By=C[/tex]

[tex]4x-y-7=0\qquad\text{add 7 to both sides}\\\\\boxed{4x-y=7}[/tex]

[tex]3x+9=\dfrac{7}{2}y\qquad\text{multiply both sides by 2}\\\\6x+18=7y\qquad\text{subtract 18 and 7y from both sides}\\\\\boxed{6x-7y=-18}[/tex]

[tex]y=-4x+12\qquad\text{add 4x to both sides}\\\\\boxed{4x+y=12}[/tex]

[tex]y=-\dfrac{3}{4}x+\dfrac{5}{4}\qquad\text{multiply both sides by 4}\\\\4y=-3x+5\qquad\text{add 3x to both sides}\\\\\boxed{3x+4y=5}[/tex]

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