I definitely need a little help with this.
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Answer:
It is given that,
there are 8 balls in the bag numbered 1 to 8
Only one ball color is gray and all others are white
P(X) = probability of getting white ball
P(not X) = Probability of getting gray ball
a) To find Probabilities P(X) and P(not X)
For event X, 1,3,4,5,6,7,8 are checked and P(X) = 7/8
for event 'not X' only 2 is checked and P(not X ) = 1/8
b) To find 1 - P(X)
1 - P(X) = 1 - 7/8 = (8 - 7)/8 = 1/8
c)1 - P(X) is same as P(not X)