Answer:
Point-Slope form: The equation of line is given by:
[tex]y-y_1=m(x-x_1)[/tex] ......[1]
where m is the slope and [tex](x_1,y_1)[/tex] is the point on the line.
From the given graph:
Consider two points i.e,
[tex](0, 1)[/tex] and (-0.5, 0)
Calculate slope:
Formula for slope is given by;
[tex]\text{Slope}(m) = \frac{y_2-y_1}{x_2-x_1}[/tex]
Substitute the given values we have;
[tex]m = \frac{0-1}{-0.5-0} = \frac{-1}{-0.5} = \frac{10}{5} =2[/tex]
Now, substitute the value of m = 2 and (0, 1) in equation [1] we have;
[tex]y-1 = 2(x-0)[/tex]
y-1 = 2x
Add 1 to both sides we get;
y = 2x+1
On comparing equation y = 2x+1 with the slope intercept form of a line (i.e, y = mx+b) then we have;
slope(m) = 2
y-intercept(b) = 1
therefore, the slope of the function:
m = 2
y-intercept(b) = 1
and the equation represents the graph: y = 2x+1