PLEASE HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!!!
The table below shows some values of f(x) and g(x) for different values of x:

Complete the chart and determine the solution of the equation f(x) = g(x).
x = −1
x = 0
x = 2
x = 25

PLEASE HELP 30 POINTS The table below shows some values of fx and gx for different values of x Complete the chart and determine the solution of the equation fx class=

Respuesta :

Since you know the value of "x", you can plug in the value for "x" in the equation.

[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

For example:

[tex]x^{-2}[/tex]  or  [tex]\frac{x^{-2}}{1} =\frac{1}{x^2}[/tex]

[tex]\frac{1}{y^{-3}} =\frac{y^3}{1}[/tex]  or  y³


x = -2

f(x) = 9x + 7

f(-2) = 9(-2) + 7 = -18 + 7 = -11


[tex]g(x)=5^x[/tex]

[tex]g(-2)=5^{-2}=\frac{1}{5^2}=\frac{1}{25}[/tex]   (idk if you should have it as a decimal or a fraction)



x = -1

f(x) = 9x + 7

f(-1) = 9(-1) + 7 = -9 + 7 = -2


[tex]g(x)=5^x[/tex]

[tex]g(-1)=5^{-1}=\frac{1}{5}[/tex]



x = 0

f(x) = 9x + 7

f(0) = 9(0) + 7 = 7


[tex]g(x)=5^x[/tex]

[tex]g(0)=5^0=1[/tex]



x = 1

f(x) = 9x + 7

f(1) = 9(1) + 7 = 9 + 7 = 16


[tex]g(x)=5^x[/tex]

[tex]g(1)=5^1=5[/tex]



x = 2

f(x) = 9x + 7

f(2) = 9(2) + 7 = 18 + 7 = 25


[tex]g(x)=5^x[/tex]

[tex]g(2)=5^2=25[/tex]



You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and [tex]g(x)=5^x[/tex], you can plug in (9x + 7) for f(x), and ([tex]5^x[/tex]) into g(x)


f(x) = g(x)

[tex]9x+7=5^x[/tex]   You can plug in each value of x into the equation


Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25

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