After being rearranged and simplified, which two of the following equations could be solved using the quadratic formula? A) 5x^3+2x-4=2x^2 B) x^2-6x-7=2x^2 C) 2x^2-3x+10=2x^2+21 D) 5x^2-3x+10=2x^2

The quadratic formula can be used to solve for x for any quadratic. Recall a quadratic is any function whose highest exponent known as degree is 2. Looking at the answer selections, A has one term with exponent 3. This isn't possible in the formula. Looking at answer C, the term with exponent 2 has the same coefficient on each side of the equal sign. When it is rearranged these will cancel out no exponent of 2 will be in the equation anymore. Only B & D work after being rearranged and simplified

shubhamchouhanvrVT shubhamchouhanvrVT · Answer 2 · 2022-06-06T13:48:10+02:00

The two equations after simplifying will give quadratic equations are:-

x ²-6x-7=2x² and 5x²-3x+10=2x².

What is a quadratic equation?

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

Solving for the quadratic equation:-

Option B:-

x ² - 6x - 7 = 2x²

- 2x² + x ² - 6x - 7 = 0

x ² + 6x + 7 = 0

Option D:-

5x² - 3x + 10 = 2x².

5x² - 2x². - 3x + 10 = 0

3x² - 3x + 10 = 0

Therefore two equations after simplifying will give quadratic equations are- x ²-6x-7=2x² and 5x²-3x+10=2x².

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