If I
understand the question correct, the hockey season ticket holder paid
$72.48 for all of the tickets at once, and then $6.00 for each game
thereafter. The second person pays $18.08 for a ticket per game.
So then let g = the number of games. The problem can be written as a system of equations:
Person 1 = 72.48 + 6g
Person 2 = 18.08g
We are looking for when the number of games for both are the same. To do
this, just set them equal to each other and solve for g.
72.48 + 6g = 18.08g
Subtract 6g:
72.48 = 12.08g
Divide by 12.08:
g = 6
So after 6 games, the two would have paid the same price.
