QUESTION 1 a
We were given that, line PQ is a tangent to the circle.
This tangent will meet the radius or diameter at an angle of
[tex]90 \degree[/tex]
This implies that,
[tex] < \: RQP = 90 \degree[/tex]
Question 1b
The other two angles of right triangle PQR are complementary.
This implies that,
[tex](5x + 20) + 3x = 90 \degree[/tex]
We group like terms to get,
[tex]5x + 3x = 90 - 20[/tex]
This implies that,
[tex]8x = 70[/tex]
[tex]x = \frac{70}{8} [/tex]
[tex]x = 8.75[/tex]
Question 1c
We substitute the value of x to determine the
value angle QRP.
[tex] \: < \: QRP = 5(8.75) + 20 = 63.75 \degree[/tex]
Question 1d
We substitute the value of x to determine the value angle RPQ.
[tex] \: < RPQ \: = 3(8.75) = 26.25 \degree[/tex]