Respuesta :

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannual, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500\left(1+\frac{0.025}{2}\right)^{2\cdot 6}\implies A=1500(1.0125)^{12}\implies A\approx 1741.13[/tex]