Question

Suppose that rectangle ABCD is dilated to A'B'C'D' by a scale factor of 3 with a center of dilation at (1, 1).

What is the approximate distance from the center of dilation to the midpoint of C'D'?
A) 3 units
B) 4.5 units
C) 6.3 units
D) 9 units

Answer 1

Answer:

The correct option is C.

Step-by-step explanation:

From the given figure it is noticed that the coordinates of vertices are C(1,-2) and D(-2,1).

Dilation by factor k with center at origin is defined as

$(x,y)\rightarrow(kx,ky)$

Dilation by factor k with center at point (a,b) is defined as

$(x,y)\rightarrow(k(x-a)+a,k(y-b)+b)$

The scale factor is 3 and center of dilation at (1, 1).

$(x,y)\rightarrow(3(x-1)+1,3(y-1)+1)$

The coordinates of C' are

$(1,-2)\rightarrow(3(1-1)+1,3(-2-1)+1)\rightarrow(1,-8)$

The coordinates of D' are

$(-2,1)\rightarrow(3(-2-1)+1,3(1-1)+1)\rightarrow(-8,1)$

Midpoint of C'D is

$(\frac{-8+1}{2}, \frac{1-8}{2})=(-3.5,-3.5)$

Distance formula is

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Distance between (-3.5,-3.5) and (1,1) is

$d=\sqrt{(1+3.5)^2+(1+3.5)^2}$

$d=\sqrt{(4.5)^2+(4.5)^2}$

$d=\sqrt{2(4.5)^2}$

$d=4.5\sqrt{2}$

$d=6.364$

Therefore option C is correct.

Answer 2

Answer:

Step-by-step explanation:

The correct answer is c.