Question

Fine the slope of a line that passes through (-2,-3) and (1,-1)

Answer 1

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-3)}{1-(-2)}\implies \cfrac{-1+3}{1+2}\implies \cfrac{2}{3}$

Answer 2

Answer:

The slope of the line that passes through $(-2, -3)$ and $(1, -1)$ is $\frac{2}{3}$.

Step-by-step explanation:

The slope of a line is represented by $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$, where the variables are $(x_1, y_1), (x_2, y_2)$.

Now, we can substitute the variables into the equation.

$\frac{(-1)-(-3)}{1-(-2)}$

Now just solve the equation.

$\frac{(-1)-(-3)}{1-(-2)}=\frac{2}{3}$