Question

A line passes through the point (6,-3) and has a slope of -3/2 write an equation in slope intercept form

Answer 1

Answer:

y = - $\frac{3}{2}$ x + 6

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

here m = - $\frac{3}{2}$, hence

y = - $\frac{3}{2}$ x + c ← is the partial equation

to find c substitute (6, - 3 ) into the partial equation

- 3 = - 9 + c ⇒ c = - 3 + 9 = 6

y = - $\frac{3}{2}$ x + 6 ← equation in slope- intercept form

Answer 2

The equation of the line with a slope of -3/2 passing through the point (6, -3) in slope-intercept form is expressed as $y = \frac{-3}{2} x+10$

The formula for calculating the equation of a line in slope-intercept form is expressed as;

$y = mx+b$

m is the slope

b is the y-intercept

Given the following parameters

m = -3/2

(x0, y0) =(6, -3)

Get the equation in the point-slope form first

$y-(-3)=-3/2(x-6)\\y+3=-3/2(x-6)\\2(y+3) = -3(x-6)\\2y+6 = -3x + 16\\2y = -3x +16 - 6\\2y = -3x+10\\y = \frac{-3}{2} x+10$

Hence the equation in slope-intercept form is expressed as $y = \frac{-3}{2} x+10$

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