Question

For the first 30 km, the bicyclist rode with a speed of v km/hour. For the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed. How much time did the bicyclist spend on the entire trip? Let t be the time (in hours), and find t if:v=15 t in terms of v is

Answer 1

Answer:

t in terms of v is $t=\dfrac{30}{v}+\dfrac{17}{v+2}$

when v=15, t will be 3

Step-by-step explanation:

We know that,

$\text{Speed}=\dfrac{\text{Distance}}{\text{Time}}$

$\Rightarrow \text{Time}=\dfrac{\text{Distance}}{\text{Speed}}$

For the first 30 km, the bicyclist rode with a speed of v km/hr. So the time taken by the cyclist to cover up 30 km is,

$t_1=\dfrac{30}{v}$ hr

For the remaining 17 km he rode with a speed which was 2 km/hr greater than his original speed i.e (v+2) km/hr

$t_2=\dfrac{17}{v+2}$ hr

So the total time is the sum of these individual times. So,

$t=t_1+t_2=\dfrac{30}{v}+\dfrac{17}{v+2}$

When v=15, t is

$t=\dfrac{30}{15}+\dfrac{17}{15+2}=\dfrac{30}{15}+\dfrac{17}{17}=2+1=3$

Answer 2

Answer:

30/v+17/v+2

3hour

Step-by-step explanation:

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