Question

What is the kinetic energy (in joules) of a .2 kg softball thrown at a speed of 40 m/sec? (answer should be in correct units)

Answer 1

m=0.2 kg

v=40 m/s

Kinetic energy is:

$\frac{1}{2}mv^2=\frac{1}{2}(0.2kg)(40m/s)^2= 160 J$

160 J