Question

What is the equation of the line that passes through the point (6,-7) and has a slope of -3/2

Answer 1

The point-slope form:

$y-y_1=m(x-x_1)$

We have the point (6, -7) and a slope m = -3/2. Substitute:

$y-(-7)=-\dfrac{3}{2}(x-6)\\\\\boxed{y+7=-\dfrac{3}{2}(x-6)}$