Question

A certain gas is present in a 12.0L cylinder at 3.0 atm pressure. If the pressure is increased to 6.0 atm, the volume of the gas decreases to 6.0L. Find the two constants ki, the initial value of k, and kf, the final value of k, to verify if whether the gas obeys Boyle’s law.

Answer 1

Answer:

$k_i=36\\k_f=36$

Explanation:

Boyle's law states that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

$P=\frac{k}{V}$

Where,

P = Pressure

V = Volume of the gas

k = Boyle's constant

Finding the initial Boyle's constant $k_i$:

$k_i=P_1V_1$

$k_i=3.0*12.2\\\\k_i=36$

Finding the final value$k_f$:

$k_f=P_fV_f\\\\k_f=6.0*6.0\\\\k_f=36$

To verify Boyle's law, the initial Boyle's constant should be equal to the final Boyle's constant:

$k_i=k_f$

$36=36$

Therefore, the gas does obey Boyle's Law.