Question

The combustion of methane gas (ch4) forms co2(g)+ h2o(ℓ). calculate the heat produced by burning 1.9 mol of the methane gas. the standard molar enthalpy of combustion of methane is 890.2kj/mol. answer in units of kj

Answer 1

Answer: The heat produced by burning of 1.9 mole of methane gas will be 1691.38 kJ.

Explanation: Standard molar enthalpy of combustion is defined as the change when 1 mole of the hydrocarbon gets completely burnt in the presence of oxygen gas at standard temperature and pressure.

Equation for the combustion of methane gas is given by:

$CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)$

We are given standard molar enthalpy of combustion for methane gas = 890.2 kJ/mol

This is the heat required for 1 mole of a gas.

So, heat required for 1.9 moles of a gas = 890.2kJ/mol × 1.9mol = 1691.38 kJ