Respuesta :
Answer:
The vertices of image are A'(0,0), B'(4,-8) and C'(-8,-8).
Step-by-step explanation:
From the given figure it noticed that the vertices of triangle are A(0,0), B(2,-4) and C(-4,-4).
The dilation with a scale factor of k centered at the origin is defined as
[tex](x,y)\rightarrow(kx,ky)[/tex]
So, dilation with a scale factor of 2 centered at the origin is defined as
[tex](x,y)\rightarrow(2x,2y)[/tex]
The vertices of image are
[tex]A(0,0)\rightarrow A'(0,0)[/tex]
[tex]B(2,-4)\rightarrow B'(4,-8)[/tex]
[tex]C(-4,-4)\rightarrow C'(-8,-8)[/tex]
Therefore the vertices of image are A'(0,0), B'(4,-8) and C'(-8,-8). The graph of image and preimage are shown below.
Dilation involves changing the size of a shape.
See attachment for the graph of the image
From the figure, the vertices of the triangle are:
[tex]\mathbf{A = (0,0)}[/tex]
[tex]\mathbf{B = (2,-4)}[/tex]
[tex]\mathbf{C = (-4,-4)}[/tex]
The scale factor (k) is given as:
[tex]\mathbf{k = 2}[/tex]
The coordinate of the image of the triangle is calculated using:
[tex]\mathbf{(x,y) = 2(x,y)}[/tex]
So, we have:
[tex]\mathbf{A' = 2(0,0)}[/tex]
[tex]\mathbf{A' = (0,0)}[/tex]
[tex]\mathbf{B' = 2(2,-4)}[/tex]
[tex]\mathbf{B' = (4,-8)}[/tex]
[tex]\mathbf{C' = 2(-4,-4)}[/tex]
[tex]\mathbf{C' = (-8,-8)}[/tex]
See attachment for the image of the dilation.
Read more about dilation at:
https://brainly.com/question/13176891