Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin. Use the polygon tool to graph the triangle.

Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin Use the polygon tool to graph the triangle class=

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Answer:

The vertices of image are A'(0,0), B'(4,-8) and C'(-8,-8).

Step-by-step explanation:

From the given figure it noticed that the vertices of triangle are A(0,0), B(2,-4) and C(-4,-4).

The dilation with a scale factor of k centered at the origin is defined as

[tex](x,y)\rightarrow(kx,ky)[/tex]

So, dilation with a scale factor of 2 centered at the origin is defined as

[tex](x,y)\rightarrow(2x,2y)[/tex]

The vertices of image are

[tex]A(0,0)\rightarrow A'(0,0)[/tex]

[tex]B(2,-4)\rightarrow B'(4,-8)[/tex]

[tex]C(-4,-4)\rightarrow C'(-8,-8)[/tex]

Therefore the vertices of image are A'(0,0), B'(4,-8) and C'(-8,-8). The graph of image and preimage are shown below.

Ver imagen DelcieRiveria

Dilation involves changing the size of a shape.

See attachment for the graph of the image

From the figure, the vertices of the triangle are:

[tex]\mathbf{A = (0,0)}[/tex]

[tex]\mathbf{B = (2,-4)}[/tex]

[tex]\mathbf{C = (-4,-4)}[/tex]

The scale factor (k) is given as:

[tex]\mathbf{k = 2}[/tex]

The coordinate of the image of the triangle is calculated using:

[tex]\mathbf{(x,y) = 2(x,y)}[/tex]

So, we have:

[tex]\mathbf{A' = 2(0,0)}[/tex]

[tex]\mathbf{A' = (0,0)}[/tex]

[tex]\mathbf{B' = 2(2,-4)}[/tex]

[tex]\mathbf{B' = (4,-8)}[/tex]

[tex]\mathbf{C' = 2(-4,-4)}[/tex]

[tex]\mathbf{C' = (-8,-8)}[/tex]

See attachment for the image of the dilation.

Read more about dilation at:

https://brainly.com/question/13176891

Ver imagen MrRoyal