Question

What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)?

k = –
k = –
k =
k =

Answer 1

Answer: k= $\frac{-2}{3}$

Step-by-step explanation:

Here, the equation of a line y=kx ------(1)

Since, According to the question this line passes through (-3,2)

Therefore, the point will be satisfy the equation of line.

Put x=-3 and y=2 in equation (1)

2=-3k

⇒ k = $\frac{-2}{3}$

Thus, the required value of constant of variation, k= $\frac{-2}{3}$

Answer 2

Answer:

The answer is k= -2/3