When a metal was exposed to photons at a frequency of 4.08× 1015 s–1, electrons were emitted with a maximum kinetic energy of 5.30× 10–19 J. Calculate the work function of this metal.
Also,
What is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 6.36× 10–7 J?

I would love an explanation if that is possible!

Respuesta :

Answer :

The work function of this metal is, [tex]21.7504\times 10^{-19}J[/tex]

The maximum number of electrons released = [tex]2.924\times 10^{11}electrons[/tex]

Solution : Given,

Frequency = [tex]4.08\times 10^{15}s^{-1}[/tex]

Kinetic energy = [tex]5.30\times 10^{-19}J[/tex]

Total energy = [tex]6.63\times 10^{-7}J[/tex]

First we have to calculate the work function of the metal.

Formula used : [tex]K.E=h\nu -w[/tex]

where,

K.E = kinetic energy

h = Planck's constant = [tex]6.63\times 10^{-34}J/s[/tex]

[tex]\nu[/tex] = frequency

w = work function

Now put all the given values in this formula, we get the work function of the metal.

[tex]5.30\times 10^{-19}J=(6.63\times 10^{-34}J/s\times 4.08\times 10^{15}s^{-1})-w[/tex]

By rearranging the terms, we get

[tex]w=21.7504\times 10^{-19}J[/tex]

Therefore, the works function of the metal is, [tex]21.7504\times 10^{-19}J[/tex]

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released = [tex]\frac{\text{ Total energy}}{\text{ work function}}[/tex]

The maximum number of electrons released = [tex]\frac{6.63\times 10^{-7}J}{21.7504\times 10^{-19}J}=0.2924\times 10^{12}=2.924\times 10^{11}electrons[/tex]

Therefore, the maximum number of electrons released = [tex]2.924\times 10^{11}electrons[/tex]

The work function of metal was 21.7504 [tex]\rm \times\;10^-^1^9[/tex] J, and the maximum number of electrons ejected are 2.924 [tex]\rm \times\;10^1^1[/tex] electrons.

Kinetic energy = Plank's constant [tex]\times[/tex] frequency of wavelength - work function

From the given,

5.30 [tex]\rm \times\;10^-^1^9[/tex] J = 6.63 [tex]\rm \times\;10^-^3^4[/tex] J/s [tex]\times[/tex] 4.08 [tex]\rm \times\;10^-^1^5[/tex] [tex]\rm s^-^1[/tex] - work function

Work function = 21.7504 [tex]\rm \times\;10^-^1^9[/tex] J

The maximum number of electrons ejected: [tex]\rm \frac{total\;energy}{work\;function}[/tex]

Maximum number of electrons ejected = [tex]\rm \frac{6.36\;\times\;\;10^-^7\;J}{21.7504\;\times\;10^-^1^9\;J}[/tex]

Maximum number of electrons ejected = 2.924 [tex]\rm \times\;10^1^1[/tex] electrons.

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https://brainly.com/question/12658742?referrer=searchResults

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