Please help, I'm late on this and I can't put words with numbers well enough to make anything readable!!!
30 points, thanks, and brainliest !!!!
Note: Remember to show all of the steps that you use to solve the problem. Be sure to use the text box where the question mark (?) first appears to show your mathematical work. You can use the comments field to explain your work. Your teacher will review each step of your response to ensure you receive proper credit for your answer. How you would convert the repeating, nonterminating decimal to a fraction? Explain the process as you solve the problem. 0.1515 . . .

Respuesta :

so, what we do is, we multiply the value by a power of 10, that moves the recurring numbers to the left of the dot, in this case we want moved the "15", so we'll need two zeros, so we'll be using 100.


[tex]\bf 0.151515\overline{15}~\hspace{7em}x=0.151515\overline{15} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{array}{|lll|ll} \cline{1-3} &&\\ 100\cdot x&=&15.1515\overline{15}\\ &&15+0.1515\overline{15}\\ &&15+x \\&&\\ \cline{1-3} \end{array}\implies 100x=15+x \\\\\\ 99x=15\implies x=\cfrac{15}{99}\implies \stackrel{simplified}{x=\cfrac{5}{33}}[/tex]

Padoru

We are presented with the repeating decimal 0.15151515...

Let [tex]x=0.151515...[/tex]

[tex]100x-x=15.151515... - 0.151515... = 15[/tex]

Why did I use 100? Since there are 2 numbers that are repeated (1 and 5), we use 100, which is 10 to the power of 2. If there was 3 repeating numbers, we would be using 1000, 10 to the power of 3.

[tex]100x-x[/tex] is the same as [tex]99x[/tex]

Thus, [tex]99x=15[/tex]

Use equation operations to solve for x, which is the fraction we desire.

Divide both sides of the equation by 99.

[tex]x = \dfrac{15}{99}[/tex]

Simplify (divide both numerator and denominator by 3)

[tex]x=\dfrac{5}{33}[/tex]

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