Question

PLZ HALP!!!!!!!! 50 POINTS!!!!!! Or 25, maybe...
A nature museum has 2008 specimens of early birds, some with 2 wings and some with 4 wings. The specimens have a total of 4038 wings.
How many specimens are there with each number of wings?

Answer 1

Answer:

there are 1997 two winged specimens and

11 four winged specimens

Step-by-step explanation:

t = two winged specimens

f = 4 winged specimens

2*t + 4*f = 4038   4038 wings

t+f =2008              2008 specimens

solve for t

t= 2008 -f

substitute t into 2*t + 4*f = 4038

2*(2008-f) + 4*f = 4038

distribute

2*2008 -2f + 4f = 4038

4016 -2f + 4f = 4038

combine like terms

4016 +2f = 4038

subtract 4016 on each side

2f = 4038 -4016

2f = 22

divide by 2

f = 22/2 =11

there are 11 4 winged specimens

t = 2008 - f

t = 2008-11

t =1997