Question

factor form
$\frac{6x { { }^{2} - 12x }^{?} }{x {}^{2} - 4 }$

Answer 1

$\dfrac{6x^2-12x}{x^2-4}=\dfrac{6x(x-2)}{x^2-2^2}=\dfrac{6x(x-2)}{(x-2)(x+2)}=\dfrac{6x}{x+2}\\\\Used:\ a^2-b^2=(a-b)(a+b)$