Question

how many moles of h2o are equivalent to 97.3 grams of h20

Answer 1

Answer : 5.405 moles of $H_2O$ are equivalent to 97.3 grams of $H_2O$

Solution : Given,

Mass of $H_2O$ = 97.3 g

Molar mass of $H_2O$ = 18 g/mole

Formula used :

$\text{ Number of moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}$

or,

$\text{ Number of moles of }H_2O=\frac{\text{ Given mass of }H_2O}{\text{ Molar mass of }H_2O}$

Now put all the given values in this formula, we get the moles of $H_2O$

$\text{ Number of moles of }H_2O=\frac{97.3g}{18g/mole}=5.405moles$

Therefore, 5.405 moles of $H_2O$ are equivalent to 97.3 grams of $H_2O$