Question

Find the margin of error if p = 65% and n = 500. Round to four decimal places.


0.0427

0.0926

0.0009

0.0414

Answer 1

Answer:

Option D is correct

Margin of error(to four decimal places) = 0.0414

Step-by-step explanation:

Given: p = 65% = 0.65 and n = 500

Error of margin (E) is given by:

$E = z^*\sqrt{\frac{p(1-p)}{n}}$

For a confidence level of 95%,

$z^* = 1.96$

Substitute the value of $z^*$ , p and n in the above formula to calculate error of margin (E) :

$E = 1.96 \cdot \sqrt{\frac{0.65(1-0.65)}{500}}$

Simplify:

E = 0.0414082288551

Therefore, the margin of error(round to four decimal places) = 0.0414