Question

What is the equation of a line, in point-slope form, that passes through (−4, 1) and has a slope of (5,7) ?
y−1=56(x+8)
y+1=56(x−8)
y+8=56(x−1)
y−8=56(x+1)

Answer 1

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

the point-slope form:

$y-y_1=m(x-x_1)$

We have the points (-4, 1) and (5, 7). Substitute:

$m=\dfrac{7-1}{5-(-4)}=\dfrac{6}{9}=\dfrac{2}{3}\\\\y-1=\dfrac{2}{3}(x-(-4))\\\\\boxed{y-1=\dfra{2}{3}(x+4)}$

Answer 2

Answer:

y-1=2/3(x+4)

Step-by-step explanation:

the other ans has a typo @ its last step but right everything else

it is not one of ur choices

the nearest is y−1=56(x+8) as it has the term "y-1"