Please answer question 6 for 25 points ! :D

Answer:
The answer is 3^4.
Step-by-step explanation:
First we're gonna use the exponent rule, so, 3^5/3^3 = 3^5-3 = 3^2.
Then our remainer is the 3^2, so we simply multiply our remaining exponent, which is the 2 from the outter-parenthesis. So 2 x 2 = 4. So its now 3^4.
[tex]\left(\dfrac{3^5}{3^3}\right)^2\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\left(3^{5-3}\right)^2=(3^2)^2\qquad\text{use}\ (a^n)^m=a^{n\cdot m}\\\\=3^{2\cdot2}=3^4\\\\Answer:\ \boxed{b.\ 3^4}[/tex]