Respuesta :
Answer with explanation:
First Method
[tex]\sqrt{50}=\sqrt{5\times 5 \times 2}\\\\=5\sqrt{2}\\\\=5 \times 1.41421\\\\=7.07105\\\\7.07 <\sqrt{50}<7.08[/tex]
Second method which is described in the question
[tex]7 < \sqrt{50}<8\\\\7^2<50<8^2\\\\(7.0)^2< 50 < (7.1)^2\\\\(7.07)^2<50 (7.08)^2\\\\7.07 <\sqrt{50} <7.08[/tex]
Answer:The √50 is between 7.07 and 7.08
Step-by-step explanation: