Question

If csc Θ = 3/2 and the angle is in quadrant II, what is sec Θ?

Answer 1

Answer:

sinθ = 1/cscθ = 2/3

cos²θ = 1 − sin²θ = 1−4/9 = 5/9

cosθ = −√5/3

secθ = 1/cosθ = −3/√5 = −3√5/5