For this case we must solve a system of two equations with two unknowns, given by "x" and "y".
We have:
[tex]y = \frac {1} {2} x + 2 (1)\\y = -2x-3 (2)[/tex]
We multiply (2) by -1:
[tex]-y = 2x + 3 (3)[/tex]
We add (1) and (3):
[tex]y-y = \frac {1} {2} x + 2x + 2 + 3\\0 = \frac {5} {2} x + 5\\-5 = \frac {5} {2} x[/tex]
Clearing x:
[tex]-10 = 5x\\x = \frac {-10} {5}\\x = -2[/tex]
We substitute [tex]x = -2[/tex] in (2)
[tex]y = -2 (-2) -3\\y = 4-3\\y = 1[/tex]
Thus, the solution of the system is[tex](x, y) = (- 2,1)[/tex]
Answer:
the solution of the system is[tex](x, y) = (- 2,1)[/tex]