For this case we must solve a system of two equations with two unknowns, given by "x" and "y".
We have:
[tex]y = 4x + 11\ (1)\\y = -2x-1\ (2)[/tex]
We multiply (2) by -1:
[tex]-y = 2x + 1\ (3)[/tex]
We add (1) and (3):
[tex]y-y = 4x + 2x + 11 + 1\\0 = 6x + 12[/tex]
Clearing x:
[tex]-12 = 6x\\x = \frac {-12} {6}\\x = -2[/tex]
We substitute [tex]x = -2[/tex] in (2)
[tex]y = -2 (-2) -1\\y = 4-1\\y = 3[/tex]
Thus, the solution of the system is [tex](x, y) = (- 2,3)[/tex]
Answer:
The solution of the system is [tex](x, y) = (- 2,3)[/tex]