Answer:
A
Step-by-step explanation:
using the Sine rule in ΔABC
[tex]\frac{a}{sinA}[/tex] = [tex]\frac{c}{sinC}[/tex]
substitute given values
[tex]\frac{8}{sinA}[/tex] = [tex]\frac{16}{sin35}[/tex] ( cross- multiply )
16sinA = 8sin35° ( divide both sides by 16 )
sinA = [tex]\frac{8sin35}{16}[/tex] = 0.28678...
⇒ A = [tex]sin^{-1}[/tex](0.28678..) = 16.67° ( to 2 dec. places )