Respuesta :

gmany

[tex]2\cos\Theta=\sqrt3\to\cos\Theta=\dfrac{\sqrt3}{2}\\\\2\cos\Theta+\dfrac{1}{2}\cos\Theta-1=\sqrt3+\dfrac{1}{2}\cdot\dfrac{\sqrt3}{2}-1=\dfrac{4\sqrt3}{4}+\dfrac{\sqrt3}{4}-\dfrac{4}{4}\\\\=\boxed{\dfrac{5\sqrt3-4}{4}}[/tex]

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