The grams of oxygen gas that can be produced is 20.6 grams of O₂
calculation
2LiClO₃ → 2 LiCl + 3 O₂
step 1: find the moles of LiClO₃
moles = mass÷ molar mass
from periodic table the molar mass of LiClO₃ =6.9 +35.5 +(16 x3) =90.4 g/mol
moles=38.7 g÷90.4 g/mol=0.4281 moles
step 2: use the mole ratio to calculate the moles of O2
from equation above, LiClO₃:O₂ is 2:3
therefore the moles of O₂=0.4281 moles x3/2 =0.6422 moles
Step 3: find mass of O₂
mass= moles x molar mass
from periodic table the molar mass of O₂ = 16 x2= 32 g/mol
mass=0.6422 moles x 32 g/mol = 20.6 grams of O₂
