Question

A 16.9 gram sample of KCl is used to mak a 250 mL KCl solution. What is the molarity of the KCl solution?

Answer 1

Answer:

0.906 gm/l

Explanation:

We know that molarity of the a solution is given by,

$M= \frac{w}{m} \times \frac{1000}{v}$, where 'M' is the molarity, 'w' is the weight of the sample, 'm' is the molar mass, and 'v' is the volume of the solution.

Molarity of a solution tells us the concentration of the solute in the solvent.

Molar mass of KCl is = 74.55

Putting the values we get,

$M = \frac{16.9}{74.55} \times \frac{1000}{250}=0.906 gm/l$

So the molarity of KCl solution is 0.906 gm/l.

Answer 2

The molarity of the KCl solution : 0.9068

Further explanation

Stochiometry in Chemistry studies about chemical reactions mainly emphasizes quantitative, such as the calculation of volume, mass, which is related to the number of molecules, elements, etc.

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

• Mole

Mole itself is the number of particles contained in a substance

1 mole = 6.02.10²³ particles

Mole can also be sought if the amount of substance mass and its molar mass is known

$\large{\boxed{\boxed{\bold{mole=\frac{mass}{molar\:mass}}}}$

• Molarity (M)

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So to find the number of moles can be expressed as

$\boxed{\bold{n=V\times M}}$

A 16.9 gram sample of KCl is used to make a 250 mL KCl solution

• mole

Molar mass of KCl is 74.5513 g/mol

$\large{\boxed{\bold{mole=\frac{mass}{molar\:mass}}}$

$\displaystyle mole=\frac{16.9}{74.5513}}$

mole = 0.2267

• molarity

$\displaystyle M=\frac{mole}{V(l)}$

Volume = 250 ml = 0.25 L

$\displaystyle M=\frac{0.2267\:mole}{0.25\:L}$

$\boxed{\bold{M=0.9068}}$

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Keywords: molarity, KCl solution,molar mass, mass