Respuesta :

the answer is 71.01 also could u please try to help me I have to turn in my work tomorrow :)

[tex]7\sqrt{27}  +5\sqrt{48} = 7\sqrt{3^2 \cdot 3}  + 5 \sqrt{3 \cdot 2^4} = 7(3)\sqrt{3} + 5(2^2)\sqrt{3} = 41\sqrt{3}[/tex]

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