Question

Jamal has the following choices for his pizza: white sauce or red sauce; white cheese or yellow cheese; and mushrooms, pepperoni or sausage. What is the probability that he creates a pizza that has red sauce and mushrooms?

Answer 1

the probability of jamal making a pizza with red sauce and mushrooms is 2/7

Answer 2

Answer:

The probability that he creates a pizza that has red sauce and mushrooms are:

                         $\dfrac{1}{6}$

Step-by-step explanation:

Jamal has the following choices for his pizza:

White sauce or red sauce; white cheese or yellow cheese; and mushrooms, pepperoni or sausage.

Let A denote the event of choosing a red sauce.

and B denote the event of choosing a mushroom.

Let P denote the probability of an event.

Now we know that event A and event B are independent.

We are asked to find:

                         P(A∩B)

Since the two events are independent.

Hence,  

$P(A\bigcap B)=P(A)\times P(B)$

$P(A)=\dfrac{1}{2}$

( Since out of 2 choices i.e. white sauce or red sauce , we have to choose red sauce)

and

$P(B)=\dfrac{1}{3}$

( Since, out of 3 choices i.e. mushrooms, pepperoni or sausage we have to choose mushroom)

Hence, the answer is:

$P(A\bigcap B)=\dfrac{1}{2}\times \dfrac{1}{3}$

i.e.

$P(A\bigcap B)=\dfrac{1}{6}$