write the answer in simplified radical form

Put x = 9 to the expression:
[tex]\sqrt{21-x}\to\sqrt{21-9}=\sqrt{12}=\sqrt{4\cdot3}=\sqrt4\cdot\sqrt3=2\sqrt3[/tex]
[tex]Used\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt4=2\ \text{because}\ 2^2=4[/tex]
Answer:
2√3
Step-by-step explanation:
subtract the numbers 21 - 9 = 12
do prime factorization 2² * 3
then apply the radical rule
√2² = 2
2√3
I hope this helps! :)