Answer:
[tex](2n+1)(n+7)[/tex]
Step-by-step explanation:
Here we are given the quadratic expression:
[tex]2n^{2}+15n+7[/tex]
Now we can use AC method to factorise it.
IN this method we first have to multiply 2 and 7.
2 multiplied by 7 equals 14.
Now we have to find two possible factors of 14 which add up to give 15.
Two such possible factors of 14 are 14 and 1.
So now we replace 15n by 14n+1n.
Rewriting the expression,
[tex]2n^{2}+14n+1n+7[/tex]
Factoring by grouping, we have
[tex]2n(n+7)+1(n+7)[/tex]
[tex](2n+1)(n+7)[/tex]
So the final factored form of the trinomial is
[tex](2n+1)(n+7)[/tex]