[tex]\sqrt{16-x}[/tex] x = 8
Since x = 8, you can plug in/substitute 8 for "x" in the equation:
[tex]\sqrt{16-x}[/tex]
[tex]\sqrt{16-8}[/tex]
[tex]\sqrt{8}[/tex]
2.82842
2.83 You answer is the 4th option
[tex]\sqrt{x+7}[/tex] x = 9
Plug in 9 for "x" in the equation
[tex]\sqrt{x+7}[/tex]
[tex]\sqrt{9+7}[/tex]
[tex]\sqrt{16}[/tex]
4 Your answer is the 1st option
