Question

What is the solution to the equation
-3d/d^2-2d-8+3/d-4=-2/d+2?

Answer 1

Answer:

If im right the answer would be  d ≓ -7.366989911

2d3-14d2+5d-3

 —————————————— • d2 = 0 • d2

       d2      

F( -7.366989911 ) is  -0.000000096  

Answer 2

Answer:

The solution of the equation is d=1.

Step-by-step explanation:

Given :  Equation $-\frac{3d}{d^2-2d-8}+\frac{3}{d-4}=-\frac{2}{d+2}$

To find : What is the solution to the equation?

Solution :

Step 1 - Write the equation

$-\frac{3d}{d^2-2d-8}+\frac{3}{d-4}=-\frac{2}{d+2}$

Step 2 - Factor the quadratic equation and take RHS to LHS

$-\frac{3d}{(d+2)(d-4)}+\frac{3}{d-4}+\frac{2}{d+2}=0$

Step 3 - Take the Least common denominator (LCD)

$\frac{-3d+3(d+2)+2(d-4)}{(d+2)(d-4)}=0$

Step 4 - Solve the numerator and take denominator to other side

$-3d+3d+6+2d-8=0$

 $2d=2$

$d=1$

Therefore, The solution of the equation is d=1.