Answer:
x2 − 14x + 49 = 0
Step-by-step explanation:
[tex]\displaystyle\\x^2-14x+49=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{14\pm\sqrt{196-4\cdot49}}{2}= \frac{14\pm\sqrt{196-196}}{2}=\frac{14}{2}=7\\ \\\boxed{x_1=x_2=7}[/tex]
