Question

Find the value of x if DE is the midsegment of triangle ABC and

DE = 5x and BC = 11x – 15.

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Answer 1

Answer

Find out the value of x.

To prove

Definition of mid- segment

It is a segment connecting the midpoints of two sides of a triangle.

It is always parallel to the third side, and the length of the midsegment is half the length of the third side.

As shown in the triangle given below.

As given

DE = 5x and BC = 11x – 15

Thus

$DE = \frac{BC}{2}$

$5x = \frac{11x-15}{2}$

$5x\times 2 = 11x-15$

$10x = 11x-15$

15 = 11x - 10x

15 = x

Therefore the value of x is 15 .